JUNIOR DEVELOPER TEST - Strings

This is a test I did for a role of junior developer that a company was recruiting for.
It is just a small little problem and they gave us I think 15 or 20 minutes. Really, it is quite simple unless you haven't manipulated strings in a while :O, then it might take a little longer to do, but it'll be done.

THE PROBLEM:
Given a string S, such as "We are coders.   Forget CVs !" the aim is to break it down into sentences, like in the example would be "We are coders" and "Forget CVs ". the '.', '?' and '!' are delimiters, so we need to break the string into a sentence when only one of those three characters occur.  
Each sentence can be formed by 1 or more words, or it can be an empty sentence. So sentence "We are coders" would be formed by 4 blocks (3 words and empty sentence).
"  Forget CVs " is formed by 2 words and empty sentence =3.
The aim is to compute what is the maximum number of blocks given a string S. In this case it would be 4.
In the example "The mountain is tall. I rather be in the beach? Oh la la  !". The would be three sentences: "The mountain is tall"(5 blocks), "I rather be in the beach?"(7 blocks) and "Oh la la  "(4 blocks). The return answer would be 7.

QUICK SOLUTION:

public static int Blocks (string S)
{
   char [] sentenceDelimiters = {'.', '?', '!'};
   int result =0;
   
   string [] sentences= S.Split(sentenceDelimiters);
   
  for (int i=0; i<sentences.Length; i++)
  {
     int countWords;
     sentences[i]= sentences[i].Trim();  // eliminates any start/end white space
    
     if (String.IsNullOrEmpty(sentences[i])) countWords =1; // test says an empty sentence counts as 1.
     else countWords = sentences[i].Split().Length +1; // add 1 to count an empty sentence.

    if (countWords > result) result = countWords;
   }
    return result;
}

To refresh knowledge about class String and its methods:

msdn.com->string class and methods 

       
 It wasn't hard, but junior developer tests are like a lotto, you never know what topic out of a zillion you might get!

PR