Thursday 18 June 2015

CODILITY.COM - LESSON 2 - MaxCounters

THE PROBLEM
You are given N counters, initially set to 0, and you have two possible operations on them:
  • increase(X) − counter X is increased by 1,
  • max counter − all counters are set to the maximum value of any counter.
A non-empty zero-indexed array A of M integers is given. This array represents consecutive operations:
  • if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
  • if A[K] = N + 1 then operation K is max counter.
For example, given integer N = 5 and array A such that:
    A[0] = 3
    A[1] = 4
    A[2] = 4
    A[3] = 6
    A[4] = 1
    A[5] = 4
    A[6] = 4
the values of the counters after each consecutive operation will be:
    (0, 0, 1, 0, 0)
    (0, 0, 1, 1, 0)
    (0, 0, 1, 2, 0)
    (2, 2, 2, 2, 2)
    (3, 2, 2, 2, 2)
    (3, 2, 2, 3, 2)
    (3, 2, 2, 4, 2)
The goal is to calculate the value of every counter after all operations.
Assume that:
  • N and M are integers within the range [1..100,000];
  • each element of array A is an integer within the range [1..N + 1].

MY SOLUTION (88% - 100% results, 80% performance, time complexity O(n+M))

using System;
using System.Collections.Generic;
using System.Linq;

class Solution {
    public int[] solution(int N, int[] A) {
        int l = A.Length;
        int [] result = new int [N];
        int maxCounter=0;                
        for (int i=0; i<l; i++)
        {
           if (A[i]>=1 && A[i]<=N)        
             {   
                result[A[i]-1] +=1;
                if ((result[A[i]-1]) > maxCounter)    
                     maxCounter = result[A[i]-1];        
             }
           if (A[i] == N+1)
            {                          
             for (int j=0; j<N; j++) result[j] = maxCounter;              
            }            
        }
        return result;        
    }

}

There is one performance test that fails:
extreme_large
all max_counter operations
>6.000 sTIMEOUT ERROR
running time: >6.00 sec., time limit: 0.49 sec.
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